Lab 3 Notes

Calculating Rise Time, Fall Time, and Delay

rise20 = cross(VT("/out") 0.2 1 "rising" nil nil nil )

rise80 = cross(VT("/out") 0.8 1 "rising" nil nil nil )

t_rise = rise80-rise20

$t_r = 12.33$[ps]

fall80 = cross(VT("/out") 0.8 1 "falling" nil nil nil )

fall20 = cross(VT("/out") 0.2 1 "falling" nil nil nil )

t_fall = fall20-fall80

$t_f = 11.98$[ps]

pdf = delayMeasure(VT("/in") VT("/out") ?edge1 "rising" ?value1 0.5 ?edge2 "falling" ?value2 0.5 )

$t_{pdf} = 21.45$[ps]

pdr = delayMeasure(VT("/in") VT("/out") ?edge1 "falling" ?value1 0.5 ?edge2 "rising" ?value2 0.5 )

$t_{pdr} = 22.69$[ps]

tpd = (pdf+pdr)/2

$t_{pd} = 22.07$[ps]

$t_{pdr} = 1.172692$[ns] $- 1.15$[ns]

$t_{pdf} = 71.44874$[ps] $- 50.0$[ps]

$t_r = 1.178133$[ns] $- 1.165857$[ns]

$t_f = 76.5474$[ps] $- 64.7758$[ps]

rise1 = cross(VT("/v1") 0.5 1 "rising" nil nil nil )

rise2 = cross(VT("/v1") 0.5 2 "rising" nil nil nil )

T0 = rise2 - rise1

f0 = 1/T0

$T_0 = 212.7$[ps] $f_0 = 4.702$[GHz]

f = \frac{1}{2tn}

Where t is the delay of a single inverter, and n is the number of inverters.

fall2 = cross(VT("/v2") 0.5 1 "falling" nil nil nil )

t = fall2 - rise1

$t = 14.14$[ps]

n = 11

$f_0 = \frac{1}{2(14.14\times10^{-12})(11)} = 4.878$[GHz]