Finished ECOMMS homework 3
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@@ -90,6 +90,4 @@ Frequency: 1kHz
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### 3c
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If the RF waveform appears across a 50$\Omega$ load, determine the average power and the PEP.
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The average power of the signal is:
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$$\langle s^2(t) \rangle = \frac{1}{T} \int\limits_{-T/2}^{T/2} 500\cos(\omega_c t + 20\cos(\omega_1 t)) dt$$
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The average power and the PEP are the same: $\frac{A_c^2}{2} \times \frac{1}{50} = 2.5$kW.
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