VLSI homework 10, ECOMMS homework 3
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# ECOMMS Homework 3 - Aidan Sharpe
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## Problem 1
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A sinusoidal signal $m(t) = \cos(2\pi f_m t)$ is the input to an angle-modulated transmitter, $A_c = 1$, and the carrier frequency is $f_c = 1$ Hz and $f_m = f_c/4$. Plot $m(t)$, and the corresponding phase and frequency modulated signals, $S_p(t)$ and $S_f(t)$ respecively. $D_p = \pi$ and $D_f = \pi$.
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```python
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f_c = 1
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f_m = f_c/4
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f_s = 8E3
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T_s = 1/f_s
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A_c = 1
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D_p = np.pi
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D_f = np.pi
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omega_m = 2*np.pi*f_m
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omega_c = 2*np.pi*f_c
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# Time samples from to 10 seconds with a sampling frequency of 8kHz.
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t = np.arange(0,10,T_s)
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# The message signal
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m = np.cos(omega_m * t)
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# The phase modulated signal
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S_p = np.cos(omega_c*t + D_p*m)
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# The time integral of the mesage signal
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M = np.sin(omega_m * t) / omega_m
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# The frequency modulated signal
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S_f = np.cos(omega_c*t + D_f*M)
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```
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## Problem 2
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An FM signal has sinusoidal modulation with a frequency of $f_m = 15$kHz and a modulation index of $\beta = 2.0$. Find the transmission bandwidth by using Carson's rule, and find the percentage of total FM signal power that lies within the Carson rule bandwidth.
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```python
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# Modulation index
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beta = 2.0
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# Message frequency
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f_m = 15E+3
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# Transmission bandwidth
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B_T = 2*(beta+1)*f_m
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```
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$\boxed{B_T = 90\text{kHz}}$
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```python
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A_c = 1
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n = np.arange(-3,4,1)
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# Evaluate the Bessel function at values in Carson rule bandwidth
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bessel_values = np.abs(sp.special.jv(n,beta))
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P_C = 0.5 * A_c**2 * np.sum(bessel_values**2))
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P = 0.5 * A_c**2
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```
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\boxed{P_c = 0.9976 P}
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## Problem 3
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A modulated RF waveform is given by $500\cos(\omega_c t + 20\cos(\omega_1 t))$, where $\omega_1 = 2\pi f_1$, $f_1 = 1$kHz, $\omega_c = 2\pi f_c$, and $f_c = 100$MHz.
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### 3a
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If the phase sensitivity $D_p = 100$ rad/V, find the mathematical expression for the corresponding phase modulation voltage $m(t)$. What is its peak value and frequency?
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$m(t) = \frac{20\cos(\omega_1 t)}{D_p} = 0.2\cos(\omega_1 t)$
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Peak value: $2 \times 10^{-1}$
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Frequency: 1kHz
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### 3b
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If the frequency deviation constant $D_f = 10^6$rad/Vs, find the mathematical expression for the corresponding FM voltage $m(t)$. What is its peak value and its frequency?
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$\theta(t) = 20\cos(\omega_1 t)$
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$m(t) = \frac{1}{D_f} \frac{d \theta(t)}{dt} = -2 \times 10^{-5} \omega_1 \sin(\omega_1 t)$
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Peak value: $2 \times 10^{-5}$
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Frequency: 1kHz
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### 3c
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If the RF waveform appears across a 50$\Omega$ load, determine the average power and the PEP.
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The average power of the signal is:
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$$\langle s^2(t) \rangle = \frac{1}{T} \int\limits_{-T/2}^{T/2} 500\cos(\omega_c t + 20\cos(\omega_1 t)) dt$$
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